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Two lines lying in a plane are said to be parallel if they never meet. Polygons
A closed figure, bounded by finite number of line segments, all lying in the same plane, is known as polygon. Sum of interior angles of a polygon having 'n' sides, = Sum of exterior angles of a polygon = 360 Triangles
A triangle is a polygon formed by 3 line segments joined end to end. Sum of interior angles of a triangle = 180 In any given triangle sum of 2 interior angles is equal to the third remote angle. AD is the median of triangle, then G is the centroid of the triangle .Centroid of a triangle divides the median AD in the ratio 2:1
Angle Bisector Theorem
If AD is the bisector of the the angle ABC then AD divided the side BC in the ratio Circle Theorem
If AC is a chord of circle then angle ABC subtended by the chord at a point B on the circle is equal to
to angle subtended at point 0 lying in the same segment ie ∟ABC = ∟ADC. Also angle ABC is half of angle AOC.
Alternate Segment Theorem
If XTB is a tangent to the circle then ∟ATB =∟ACT. = where Area of a circle of radius r = Area of a square of side Length of diagonal of square = Area of rectangle of length l and breath b= lb volume of cube of edge length length of cube = Volume of sphere of radius r = Volume of hemisphere of radius r = Surface area of cube = Surface area of sphere = Surface area of hemisphere =
SOLVED EXAMPLES
The sum of the areas of two circles, which touch each other externally, is 153
(1) 4 (2) 2 (3) 3 (4) none of these.
SOLUTION
Let the radii of the 2 circles be and solving we get, ratio of the larger radius to the smaller one is 12 : 3 = 4 : 1 hence option (1) is the answer.
QUESTION
In the adjoining figure, points A, B, C and D lie on the circle. AD= 24 and BC = 12. what is the ratio of the area of
(1) 1:4 (2) 1:2 (3) 1:3 (4) data insufficient.
SOLUTION In ( a chord of a circle subtends equal angel at all points on the circumference, lying in the same segment) similarly ∟ BCD = ∟ BAD and ∟ BEC = ∟ AED Therefore Now Hence QUESTION (2) (3) (4) data insufficient
SOLUTION
l ( cp) = l (cr) ( since tangents drawn from the same point are equal) hence l(BC) = l( CD) ( points P and R are midpoints of BC and CD as OP is ┴BC and OR ┴ CD) Therefore m( arc BXC) = m(arc CYD) Hence answer is option c)
But m(arc BXC ) =
therefore m(arc BZD) =
Therefore m(BCD) =
Hence m∟PCR =
m∟POR = 2m ∟PQR =
m∟OPC + m∟ORC =
Hence m∟POR + m∟PCR =
Therefore
QUESTION
Two circles of radius 3 units and 4 units are at some distance such that length of the transverse common tangents and the length of their direct common tangents are in the ratio 1: 2 . What is the distance between the centres of those circles? (1) (2) (3) 8 units
(4) cannot be determined .
SOLUTION
Let x = distance between the centres of the circles. T= length of the transverse common tangent. D = length of direct common tangent.
And
then, t =
also d =
=
Since
hence
hence x = from 1) and 2 ) we get d = 8 units hence answer is option 2 ).
Add CommentComments
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and
, then
= 15 (given)
=
(given)
= 153
= 12 and
= 3

and
, ∟ CBA = ∟ CDA.
( AAA similarity rule)
hence option b).
and
are two concentric circles while BC and CD are tangents to
at point P and respectively. AB to the circle
, which of the following is true?

























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deepak5949 : Solution to second illustration of geometry is incorrect.
The answer should be 1:4 and not 1:2 because ratio of area is required to be calculated.
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: material is good but tests are not workin ...it would be really helpful if the problem is sorted out asap
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